Problems

All references are to A. Einstein  "Relativity, The Special And The
General Theory" Methuen & Co. 1920
The theory of relativity as expounded by Einstein gives a very clear
insight into what happens in the real world, especially at extremes of
velocity and/or mass. There are, however, some questions which need
answering.
I include this link to professor Dingle's book, because anybody who has the slightest doubt (and in fact anybody who does not) about the truth of the Theory of Special Relativity should read it. I read it long ago, and reread it recently. I was astounded by it  both times. It is even more relevant now than when professor Dingle wrote it in 1971. I urge you to read it with an open mind. Science at the Crossroads.
Three other people deserve a mention here. They are Bernard Burchell, who wrote the web page Alternative Physics and rewrote my original version of "8. The Twin Paradox" (which I first put on a science forum) to make it more realistic and more readable. Second Hans Zweig, who wrote Relativity Unraveled They have both helped me tremendously. Third is the late Homer Tilton, who very kindly sent me a free copy of two of his and Florentin Smarandache's books "Begin The Adventure" and "Today's Take On Einstein's Relativity".
1. The Lorentz transformations
2. Definition of simultaneity
3. Clocks in motion
4. Clocks on the Moon
5. The equality of inertial and
gravitational mass
6. The constancy of the velocity of
light
7. Speculation on light
8. The twin paradox
9. Experimental evidence on the constancy
of the
velocity of light
10. Conclusions
11. Appendix
When Hendrik A. Lorentz devised his transformation formulae in 1890 he
thought that they applied only to electrically charged bodies, but
Einstein incorporated them into his special theory of relativity
assuming that they applied to all bodies. The theory tells us that mass
increases with velocity, becoming infinite at the speed of light.This
is the equation for mass increase.
m = m0 / sqrt( 1 ( v / c )^2)
where m = the mass of the body
m0 = the rest mass (proper mass)
v = the velocity of the body
c = the velocity of light
Lorentz was however nearer the mark. Any body which has been
accelerated to an appreciable velocity for the increase in mass to be
tested (and proved?) has been accelerated by an external force which is
itself electromagnetic and therefore constrained to the speed of
light. These formulae therefore apply only to bodies which receive an
acceleration from an external force, and the increase in mass (and
length contraction) is with respect to the reference frame from where
the force originated. The increase in mass (and the length contraction)
is an illusion. If an electro magnetic force force is used to
accelerate a body, the electro magnetic field is itself constrained to
the speed of light, so it cannot accelerate the body past that speed.
The observed effect is as though the body has increased in mass.
A simple analogy (probably oversimple  so please don't take it too
literally) may help. A tow truck (all tow trucks used in this example
have a top speed of 20mph, but the drivers do noy know this) goes out
to rescue a broken down lorry. It starts the tow, but the driver cannot
get it to go faster than 20mph. The driver calls for assistance, and
another tow truck arrives to help. Now there are two tow trucks pulling
together, and therefore twice the force. The broken down lorry can be
accelerated more but still cannot be moved faster than 20mph. They then
try to measure the mass of the lorry by hitting it from behind with a
tow truck. When the lorry is stationary, and the tow truck hits it at
20mph, it can push the lorry forwards for some distance, eg 20 feet.
When the lorry is moving slowly, the push would be nearer 15 feet, and
as they are approaching 20mph, the acceleration to the lorry from the
push gets less and less, until at
20mph the acceleration is zero. The drivers are puzzled at first, then
use the Lorentz equations to find out what is going on. They use 20mph
in place of c, and conclude that the mass of the lorry increases with
speed, becoming infinite at 20mph. This conclusion fits relativity
theory. The more power they apply, the more the mass increases and the
less the speed increases, until at 20mph, all the power goes to
increase the mass, and none to increase the speed. It does not matter
how many tow trucks are used, the result is the same, 20mph is the
limiting velocity.
Imagine now a space rocket, which is propelled by ejecting a small
amount of matter (the rocket exhaust) at high speed from the rear, so
imparting a thrust in the opposite direction. We will assume that the
exhaust velocity is 3,000 m/s and the mass of the rocket is 30,000 Kg
(very similar to NASA's MercuryRedstone rockets). Now we can use the
Lorentz transformation to find the new mass. The velocity between
exhaust and rocket is 3,000 m/s, so :
m = m0 / sqrt( 1  ( v / c )^2)
m = mass of rocket at velocity v as measured by the essential observer
(Remember that Einstein's observer, properly called the essential
observer, is always at rest relative to the motive force. In this
example therefore, the essential observer is in the same frame as the
rocket exhaust).
m0 = 30,000 Kg (proper mass of rocket or rest mass when v = 0)
v = 3,000 m/s  rocket's velocity relative to the exhaust
c = 300,000,000 m/s
m = 30000 / sqrt( 1  (3000 / 3e8)^2) = 30000.0000015000000001125 Kg
The mass increase is therefore 0.0000015 Kg or 0.0015 gram which is
simply not measurable compared to 30,000 kilograms. For all intents and
purposes the mass increase is zero. A further point to note here is
that the mass increase is measured against the exhaust which is
providing the motive force, and no matter what the velocity of the
rocket when measured against its starting point (or anything else for
that matter), the velocity between rocket and exhaust never changes, so
the rocket mass is always 30,000.0000015 Kg (disregarding the loss of
mass due to fuel used). In other words, the mass is fixed at
30,000.0000015 Kg for the values used above between rocket and exhaust,
and the extra 0.0000015 Kg is an insignificant amount. As there is no
significant mass increase with velocity, and certainly no accumulative
mass increase, there is no theoretical upper limit to the velocity of
the rocket.
It therefore follows that as the mass increase is virtually zero, m
aproximates very closely to m0. If the acceleration is regulated to 1g
for the comfort of the crew, the space ship can reach an enormous
velocity, and time on this space ship will pass at exactly the same
rate as back at home on earth. "The effects of gravity are
indistinguishable from the effects of acceleration " [AE] (with the
qualification in section 5).
I know that relativists would say that the mass increase has to be
measured relative to the starting point of the rocket, but why is that?
Einstein used the (essential) observer against which to measure the
mass
increase, with the tacit assumption that the starting point was where
the propulsion unit was located, as in a particle accelerator. With
that assumption, it is reasonable to refer the mass increase to the
starting point. If we assume the propulsion unit (rocket motor) is
remote from the rocket, then it is perfectly true that the rocket
cannot exceed the speed of the rocket exhaust, as a particle in a
particle accelerator cannot exceed c.
This is analogous to a space vehicle which uses light sails for
propulsion. The sails are deployed in the vicinity of a star (the sun),
and the light hitting the sails imparts a tiny acceleration away from
the sun. This acceleration will propel the vehicle away from the sun,
and the velocity will gradually but steadily increase. As the vehicle
approaches light speed however, the energy from the light striking the
sails gets less and less, and the acceleration gets less and less.
Quote from "Begin The Adventure" by Homer Tilton and Florentin
Smarandache.
Begin
the Adventure
"A sailing vehicle which depends on light from the sun to accelerate it
remains in that way connnected to the sun, its reference is the sun,
and its speed is limited to less than the speed of light c, relative to
the sun. Propulsive energy cannot reach a vehicle traveling away from
the sun faster than that. It is limited to the speed of light for the
same reason that a cablecar is limited to the speed of the cable
pulling it."
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Einstein uses lightning strikes at two places on the railway track, and
says that although they can be said to be simultaneous as judged from
the embankment at a vantage point exactly equidistant from them, when
judged from the moving train, they are not. He uses this as an argument
for there being a different time in moving frames of rerefence.
I have difficulty in accepting this argument for the following reasons.
In judging whether the lightning strikes are simultaneous, he uses
light itself as a medium for carrying the information to the observer,
without making any correction for the known finite velocity of light.
Any number of
other observers on the embankment, who are positioned so as not to be
equidistant from the two lightning strikes, see the same two lightning
strikes, but do not observe them to be simultaneous, and indeed,
observe the timing difference between them to vary
depending on where on the frame they are. This leads us to the
conclusion that there can be an infinite number of time scales within
one frame of reference  a conclusion which is not in accord with
reality.
Also, we could, with equal validity, have visualised two workmen with
hammers, and used sound to convey the information to the observer. The
results then achieved would be markedly different from those using
light, but nonetheless would be perfectly valid. Of course you point
out that we should use the fastest medium that we can  which is light.
Yes  use it by all means, but acknowledge the fact that it has a
finite velocity and compensate for it. To get accurate results we
should be using as a medium something which carries the information
instantaneously  but we know of no such medium. If we postulate the
existence of such a medium, and use it in a thought experiment, two
occurrences judged to be simultaneous from the embankment (wherever the
observer is positioned) will also be judged to be simultaneous from the
moving train.
Chapter IX, paragraph 2 states "Are two events ... which are
simultaneous with reference to the railway embankment also simultaneous
relative to the train? We shall show directly that the answer must be
in the negative."
"Events which are simultaneous with reference to the embankment are not
simultaneous with respect to the train, and vice versa (relativity of
simultaneity)."
Let us put our trust in the able meteorologist, and
position ourselves on the embankment exactly equidistant (at point M)
from the two lightning strokes A and B. An observer in the speeding
train at position M* is exactly at position M on the embankment when
the lightning strokes occur, but as he is speeding towards B, and away
from A, he sees the flash from B before he sees the flash from A, and
assumes them to be not simultaneous. If I now tell him the velocity of
light, the velocity of his train, and the distance M to A (which is the
same as M to B), he can easily work out the distance that he has
travelled and the distance that the light has travelled. This will tell
him that the lightning strokes were in fact simultaneous.
The inference from this discussion is that when the velocity of light
is taken into account and compensated for, an occurrence judged to be
simultaneous in one frame is also simultaneous in another. Einstein
uses this definition of simultaneity to determine that one reference
frame has a different time scale to another which is in (non
accelerated) motion relative to it, but when the velocity of light is
properly compensated for, there is no need for different time scales,
and absolute time can be used throughout all reference frames, whatever
their (non accelerated) motion. This however, comes into conflict with
the assumption that the velocity of light is the same in all reference
frames, which is discussed in section 8.
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Most physics books use a light clock in their proof of the time
dilation effect, one "tick" of the clock being the time it takes a
pulse of light to travel from the source to a mirror and back. When the
pulse arrives back at the source, the electronics ensures that another
pulse is initiated, ad infinitum. The observer O also sees the pulses
of light as they are initiated.
In A the clock is at rest relative to the observer (both are in
reference frame F1), and the light pulse travels the dotted path to the
mirror and back in T = 2L/c. In B to D, the clock is moving (now in
reference frame F2) relative to the observer who is still in F1, and he
sees that the pulse has further to travel  hence the time dilation.
When the clock is in motion relative to the observer in F1, the
observer sees the clock running slow according to the Lorentz equation
:
T* = T / sqrt( 1  ( v / c )^2
This time dilation depends on the velocity of light being the same for
all observers. Bear in mind that this not observable in any real sense.
It is inferred, and because of this inference it is also called a
"perceived" velocity. Note that an inferred or perceived velocity is
not an actual velocity, and Einstein himself used the word "judged"
when refering to this time dilation. On page 87, we can read this :
"As judged from K, the clock is moving with velocity v; as judged from
this reference body, the time which elapses between two strokes of the
clock is not one second, but 1 / sqrt( 1  (v^2 / c^2)) seconds, ie a
somewhat larger time. As a consequence of its motion the clock goes
more slowly than when at rest. Here also the velocity c plays the part
of an unattainable limiting velocity."
Note that very misleading penultimate sentence. The impression is given
that the clock is actually running slow, not just judged to be running
slow. The last sentence is equally misleading. The unattainable
limiting velocity is just as judged from K, and not physically
unattainable.
Remember that the above discussion depends on the velocity of light
being the same for all observers. This has not been proved, only
inferred. For a detailed discussion on light, go to Alternativephysics/light
This is an excellent web page by Bernard Burchell.
Let us put the clock far out in space, so there is no reference point
as to its velocity, or equivalently, imagine the clock alone in the
universe. Let us further imagine that it is in a perfect vacuum. In
line with the discussion in section 8 of this paper about what
constitutes a vacuum, I shall define a perfect vacuum as there being no
atoms whatever in the path of the light beam, no matter what the
velocity of the clock or its position in space. Now we have absolutely
no way of knowing whether it is in motion or not. We are in F1, measure
the clock's rate, and find one tick to be T = 2L/c. The light pulse
has travelled the path as in A. Now a force of 1G is applied for 4,252
hours, so the clock is accelerated, and then the force removed. The
clock must now be at half the speed of light relative to its velocity
during the first measurement of its rate, but of course there are no
reference points, so there is no way of knowing this. The rate of the
clock is measured, and found to be T = 2L/c. In a vacuum, in its own
reference frame, the rate of the clock does not alter.
This paragraph agrees with Einstein, but the next paragraph is in
conflict with Einstein.
Now the same experiment is done in a medium, which could be air. We
will neglect the fact that air resistance will stop us reaching high
velocities. The observer in the clock's reference frame notes that he
is stationary with respect to the air, and checks the clock's rate,
which he finds to be T = 2L/(c/n). The air then starts to move (in
other words the wind starts to blow, and it blows at half the speed of
light), the observer again measures the rate of the clock (he is
stationary with respect to the ground, but he is standing in a rather
strong wind). He finds that the clock is running slow, as shown in
Fig.2 B to D, according to the equation :
T* = T / sqrt( 1  v^2 / ( c / n )^2)
The index of refraction of the medium is n.
The conclusion is that in a medium, where that medium can flow
unimpeded through the path of the light pulse, moving clocks can go
slow, even within their own frame of reference. If the clock's
physical frame impedes the flow of the medium, and slows it down to a
value which is less than its value away from the physical frame, the
clock will not run as slow. If the clock is completely enclosed, e.g.
in an enclosed vehicle which is travelling at half the speed of light,
the enclosed medium is also travelling at that speed, and the clock's
rate is T = 2L/(c/n). Popular teaching states that all clocks run slow
when in motion relative to the observer. What we have just discovered
is that when in a medium, a clock does run slow at velocity, even in
its own reference frame.
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Let us expand on the discussion about clocks.
When Einstein published his paper The General Theory of Relativity in
1915, one of the things that it predicted was that gravity affects
time. The lower the gravity, the faster time flows, the higher the
gravity, the slower it flows. It would appear that this prediction has
been proved correct, but has it?
There is another school of thought, and one which I subscribe to. Time
is not running faster in lower gravity (ie at the top of a mountain as
in a popular example), it is quite simply the clock which is running
faster.
Here is a thought experiment which proves my point, and it could be
very easily (but not cheaply) performed in actuality.
Place an atomic clock on the moon alongside a pendulum clock. A
pendulum clock keeps time according to the formula P = 2π * √(L/g).
The only two variables are the length of the pendulum (L) and gravity
(g = 9.83 m/s^2 here on Earth, and 1.62 m/s^2 on the moon). The gravity
on the moon is 1/6 of that on Earth, so a pendulum clock with
a pendulum length of 0.1 meter (100mm) would run at one complete
oscillation of the pendulum in 0.6340 seconds here on Earth, but on the
moon it would take 1.5607 seconds. The atomic clock is affected to a
far lesser extent. Over one year, the moon atomic clock would run
faster than the Earth atomic clock by 0.02 seconds per year, a trifling
amount which can be ignored in this discusion.Here are the maths for
those interested.
P = period of pendulum = 2 * pi * sqrt( L / g )
L = length of pendulum
g = gravitation force
Earth : P = 2 * 3.1416 * sqrt( 0.1 / 9.83) = 6.2832 * sqrt(0.0102) =
6.2832 * 0.1009 = 0.6340 seconds
Moon : P = 2 * 3.1416 * sqrt( 0.1 / 1.62) = 6.2832 * sqrt(0.6170) =
6.2832 * 0.2484 = 1.5607 seconds
While the atomic clock on the moon counts 2.46 seconds, the pendulum
clock would count one second.
This of course is assuming that all other factors are the same,
probably the most important being temperature, but even a large
temperature change would be nowhere near the effect of the gravity
change. For example, if the temperature of the pendulum is increased by
300 degrees centigrade, which is quite possible moving from shade to
direct sunlight on the moon, its length would increase by around 0.3%,
and the period would increase by a small amount.
Moon @ n+300 degrees C :
P = 2 * 3.1416 * sqrt( 0.1003 / 1.62) = 6.2832 * sqrt(0.0619) = 6.2832
* 0.2488 = 1.563 seconds
The heat effect is negligible in comparison to the gravity effect.
As stated above, because of the reduced gravity, the atomic clock will
run faster on the moon than the Earth by around 0.02 seconds per year.
As this experiment is confined to the moon, there is no need to take
into account any SRT time dilation as seen from Earth. If Einstein is
correct, and it is time itself which has speeded up, the pendulum clock
will speed up and agree with the atomic clock. This claim is absurd, as
the pendulum clock will run as defined by gravity and pendulum length
alone, so the two clocks will disagree.
Which clock is correct? The answer is neither is correct because they
have been calibrated on Earth. Gravity is affecting the rate of both
clocks, not altering the passage of time. The atomic clock is of course
affected by gravity to a far less extent than the pendulum clock, and
in the opposite sense. The pendulum length of 100mm has been chosen as
a clock this size can easily be stowed on the moon lander and kept in a
shock proof container until the lander is on the moon. It can also be
left in the lander shielded from direct sunlight for the duration of
the experiment. Also, the duration needed to notice the difference in
timekeeping is very short. After 2 minutes and 27 seconds acccording to
the atomic clock, the pendulum clock is reading one minute, so the
experiment can be rerun many times while the lander is on the moon.
I am here assuming that the moon lander has an atomic clock on board,
but have not been able to find any firm evidence if this is the case.
Due to the large difference in the timing, a simple wristwatch would do
the job very adequately, as the wristwatch is not affected by gravity,
and will run at the same rate on the moon as here on Earth.
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In chapter XIX, Einstein makes the following statement.
"Bodies which are moving under the sole influence of a gravitational
field receive an acceleration, which does not in the least depend on
the material or the physical state of the body. For instance, a piece
of lead and a piece of wood fall in exactly the same manner in a
gravitational field (in vacuo) when they start off from rest or with
the same initial velocity."
When watching a piece of lead and a piece of wood fall, they appear to
fall in exactly the same manner. They do not. The lead actually falls
faster, but the difference in acceleration is so minute that it cannot
be measured, and can be completely ignored under all but very extreme
circumstances.
The Equivalence Principle (chapter XX) states "It is not possible by
experiment to distinguish between an accelerating frame and an inertial
frame in a suitably chosen gravitational potential, provided that the
observations take place in a small region of space and time".
Einstein states (chapter XX) that all objects when dropped, will fall
to the floor with equal acceleration, whether the chest is in a
gravitational field or is being accelerated by an outside force. We are
now in a position to show that this is not the case. Appearances can be
deceptive. We will assume that we are standing on the surface of the
Earth. If you picture a mass the equivalent of the Earth, but
compressed to a size similar to that of the wood or lead under
discussion (it is immaterial what this mass is, but it might be
convenient to picture a miniature black hole), and hold it suspended by
some means, when that mass is dropped, the observed acceleration will
not be 9.8m/s^2, but 19.6m/s^2 . As the Earth's gravity is the former
value, and as is that of the miniature black hole, we can immediately
see that the gravitational attraction is a result of the attraction of
the two bodies' gravitational fields. This applies whatever the mass
of the bodies, and explains why the wood and the lead appear to behave
the same  their mass is so tiny compared to that of the Earth, that
for all practical purposes when dealing with the Earth, they are
identical in mass.
Referring to Einstein's book again, if the man in the chest is being
accelerated at 1G by an outside force (the hypothetical being pulling
on the rope, or a reaction motor etc) and drops a piece of lead or a
miniature black hole, they will both fall with an acceleration of
exactly 9.8m/s^2  not a hair under or over. The objects are quite
simply left behind as the chest accelerates away, and will hit the
floor of the chest after 2 seconds if they are at a height of 20 meters
to start with. [experiment 1].
Let us now assume that he is in the gravitational field of the Earth
with the floor of the chest standing on the surface of the Earth. The
objects are again at a height of 20 meters, so that at 9.8m/s^2
acceleration, they would take 2s to hit the floor. The piece of lead
does indeed fall at that rate, but the miniature black hole falls at
19.6 m/s^2 (actually the miniature black hole and the Earth will each
fall towards each other with an acceleration of 9.8m/s^2 each, giving a
total acceleration of 19.6 m/s^2), and hits the floor after 1.4s .
[experiment 2]
To summarise then, if the experiment is done in the accelerated chest,
the objects will hit the floor after 2s. If the experiment is done on
the Earth, the black hole will hit the floor after 1.4s, while the lead
will hit the floor after 2s. He can immediately decide from this
experiment whether he is in a gravitational field or is being
accelerated by an outside force. If a black hole with a mass the same
as that of the Earth falls faster than a piece of lead, then so does a
mass of half the Earth, as does a mass of one hundredth, or a
thousandth etc. In principle, if the man's instruments are sensitive
enough, he can detect whether he is in a gravitational field or being
accelerated, whatever the mass of the objects which he drops.
When watching a piece of lead and a piece of wood fall on Earth, they
appear to fall in exactly the same manner. They do not. The lead
actually falls faster, but the difference in acceleration is so minute
that it
cannot easily be measured, and can be ignored for all practical
purposes.
Is it possible that Einstein did not know this? When Johannes Kepler
wrote his equations for planetary orbital motion in the early part of
the 17th century, he used the masses of both the primary and secondary
bodies, so he knew they had to be additive.
Some are rather specious, like saying that a miniature black hole would
have gravity gradient effects. Yes it would. That in itself proves that
gravity and acceleration are different. The objection I liked most
however was that if I was correct, then a heavy satellite would orbit
faster than a lighter one (in the same orbit) . Yes, absolutely
correct. But, as above, the effect is far too small to be noticed. This
got me to wondering just how large (massive) a satellite would have to
be for this effect to be noticed, which in turn led to a rather
unexpected conclusion.
Here is the scenario, and although a satellite has not been put into
orbit at the stated distance, there is no reason why it cannot be, so
in that respect, it is real. I am going to put a satellite into a
specific orbit and calculate its orbital period and velocity. I will
then calculate the orbital period and velocity of a heavier satellite
in the same orbit.
The orbits are assumed to be circular.
The units used are Kilograms, meters, and seconds. The orbital distance
is 384,900,000m from the centre of the earth. The formula used to
determine the satellite's period (Ps) is :
Ps = 2 * pi * sqrt( R^3 / G * ( Me + Ms ))
Where R = distance to satellite from the centre of the earth (or to be
more precise from the centre of mass of the earth satellite system) ie
orbit radius = 384,900,000m
G = the gravitational constant = 6.67e11
Me = the mass of the earth = 5.97219e24 Kg
Mm = the mass of the moon = 7.34767e22 Kg
Ms = the mass of the satellite (for a man made satellite not normally
taken into account, here it is assumed to be 1,000 Kg)
I used Fortran to create a flexible program to calculate orbital
velocities from various orbits and masses. The results from using a
calculator may not be an exact match but will be close enough. The
program is available here for you to check and experiment with, but it
treats the
masses as point sources, so will not be accurate with a low radius
orbit around a large mass :
http://problemswithrelativity.com/sat11.exe
The source code is here :
http://problemswithrelativity.com/sat11.f95
Ps = 6.2831853 * sqrt( 384,900,000^3 / 6.67e11 * (5.97219e24 + 1,000))
= 27.51428811520548 days.
For a satellite of 1,000,000,000 Kg the period (in seconds) is the same
to 9 decimal places. It can now be seen why the mass of a man made
satellite is not normally taken into account when calculating orbital
velocity, as increasing the mass a millionfold will result in an
orbital period difference of 2e10 seconds in 27.5 days.
The circumference of the orbit is :
C = 2 pi R = 6.2831853 * 384,900,000 = 2,418,398,092.031479 m
Therefore the velocity of the satellite is :
Vs = C / Ps = 2,419,371,395.58 / 2,378,191.224559946
= 1,017.31573486328125 m/s
The orbital radius used above is the radius of the moon's orbit so now
its period is calculated :
Pm = period of orbit of the moon.
Mm = mass of the moon = 7.347673e22 Kg
Pm = 2 * pi sqrt( R^3 / G * ( Me + Mm ))
= 6.2831853 * sqrt(384,900,000^3 / 6.67e11 * (5.97219e24 + 7.34767e22))
= 2,362,744.336301510490677977736859628 seconds
= 27.346577966452667 days
The circumference of the moon's orbit is the same as the satellite's
(but not concentric with it) C = 2,418,398,092.031479 m
The velocity is :
V = C / Pm = 2,418,398,092.031479 /
2,362,7744.36301510490677977736859628
= 1023.5547 m/s
The moon is faster than the man made satellite by 6.23895263671875 m/s,
and if the satellite were launched to be on the opposite side of the
earth from the moon when it went into orbit, the moon would gradually
catch up with it until they collided. This would take about 6 years.
Using the programme, put the Earth into the same orbit as Jupiter, you
will see that they collide in about 12,000 years
Here is the unexpected conclusion which has emerged: No trinary star
systems will be found in the universe. I define a trinary system as 1)
a system in which the central more massive body has two other bodies in
orbit around it in the same plane and which are nearly equal in orbit
radius, or 2) where there are three bodies orbiting around their common
centre of mass.
If a star system such as 1) formed in the first place, the two stars
which were similar in mass but less massive than the primary would
collide to form a binary system: or if 2) the triangle formed by the
three stars was equilateral (possible but not probable), due to the
differing velocities this triangle would shift to be non equilateral
(this would seem to be a more probable starting point, and is similar
to system 1), and then the two closest stars would approach and
collide. As they did so, a binary system would form. A trinary system
can only exist for a very short time relative to the age of the
universe, and could only be found in very young star systems.
The calculations above show that a trinary star system is not stable.
As can be seen from the above, because satellites of differing masses
in the same orbit move at different speeds, there will not be any
trinary systems in the universe, except perhaps in very young star
systems, which will not last long before they collapse.
This thought experiment stresses the distinction between the force of
gravity and other forces with which we are familiar, such as the force
of an engine pulling and accelerating a train, or the powder in a gun
which accelerates a bullet to produce its muzzle velocity.
To distinguish the force of gravity from such other forces consider an
idealized experiment in which a train is moving along an embankment on
a planet on which the force of gravity is negligible. In one case we
let an engine accelerate the train. In a second case we imagine a large
body ahead of the train which attracts the train due to its
gravitational pull. We can also imagine this second case as a train
falling, or racing, to earth.
If the train were in uniform motion then it would be valid to compare a
walk forward on the train with a laser firing a pulse of light, or a
gun shooting a bullet from the rear of the train in the direction of
the train's motion. The
velocity of the walker, the bullet or the photon remains constant
relative to the velocity of the train.
But if the train is accelerating because of the engine pulling it this
is no longer true. In that case the walker, at each step, is in touch
with the instantaneous velocity of the train, so that his walk can
remain essentially constant with respect to the instantaneous velocity
of the accelerating train. But the bullet or the laser beam do not
remain in contact with the train so their velocity will decrease
relative to that of the accelerating train as time passes.
On the other hand, if the train were falling towards earth, or pulled
forward by a large gravitational mass, the acceleration would be due to
gravity and the bullet fired from the gun (and possibly the laser
light) would also be subject to the continuing force of gravity so the
velocity relative to that of the train would be constant as is the case
for the walker. This differentiates the case of gravitational
acceleration from the force producing acceleration which acts only on
the train.
This thought experiment was devised by Hans Zweig, and is in his book,
which can be found at relativityunraveled.net
Return to menu.
Because of the principle of relativity, light ought to have the same
velocity, no matter which frame of reference we are in. Various
measurements have been made by eminent physicists who have come to the
conclusion that the velocity of light is the same in all frames of
reference.
This statement appears to hold true, as the velocity of light has been
measured in various frames of reference which are in uniform
translation with respect to each other. To put this succinctly, if the
velocity of light is measured from a certain star which is at rest
relative to us, it is found to be 300,000 Kilometers per second (Km/s).
If the same experiment is done with a star which is approaching us at
1,000 Km/s, it might be thought that the velocity of light would be
measured at 301,000 Km/s. This is not the case, the velocity of light
is still measured at 300,000 Km/s. This difficulty led Einstein to his
theory of time dilation. Chapters VIII & IX.
There are however, two snags. The first is that whatever the speed of
approach or recession, when the star's light reaches our atmosphere,
it slows down (or speeds up), and assumes the velocity for the
atmosphere's index of refraction. The velocity of light in our
atmosphere is not c, but a smaller value which is c/n, where n is the
index of refraction of the "standard" atmosphere. c/n = c/1.00029 =
299,900,000m/s approximately. The second is the rather arbitrary use of
the word vacuum. Einstein made great importance of being precise in his
terminology, so there could be no misunderstanding, and yet a vacuum
is not defined. The very terms solid, liquid, and gas are themselves
rather arbitrary, and depend on temperature and pressure, so what
exactly is a vacuum? Is it one atom per cubic millimeter on average? Is
it one atom per cubic centimeter? Is it one atom per cubic meter? Space
is not a vacuum, it is full of dust and other particles, and this makes
it a very rarefied gas with its own index of refraction. In fact, in
interstellar space, the density is an average of 1 atom per 10
centimeters, while in the vicinity of the Sun, the density is much
higher at about 1 atom per centimeter. Light therefore travels through
space as it travel
s through any other medium, at a speed of c/n relative to that medium.
The MichelsonMorley experiment is often quoted as proving the
constancy of the velocity of light, but it was set up to look for (or
more correctly, to prove, an aether drift). The light source and the
observer were stationary with respect to each other, and the experiment
was done on the surface of the Earth, so how could this experiment
prove whether c is constant with respect to the source or the observer
or both or neither? The way the MichelsonMorley experiment was set up
is akin to trying to find the windspeed by setting up an anemometer in
a closed room. The anemometer has to be outdoors, and the further away
from any obstacles, the more accurate the reading will be. I find it
strange that a direct experiment to prove the constancy of the velocity
of light has never been done. It has only been inferred and never
proven directly.
There is an "aether", but not one in the classical sense, and that is
why the MichelsonMorley experiment could not detect it. That
experiment was done on Earth where the speed of light is c/n relative
to the earth (or more precisely to the atmosphere), whatever its
direction or the direction of the earth. Let
us move the MichelsonMorley experiment into space, and in fact well
away from the Earth. We will put it on an interplanetary probe, and on
an extension arm some distance from the probe body. Do the experiment
well away from any planet or other large body, aligned with one arm on
a line pointing to the Sun, and the other arm will then be at right
angles to the Sun. One arm is now at right angles to the aether drift
and one arm is aligned with it. The result of the experiment will be an
aether drift towards the Sun. What has been measured here is the dark
matter (DM), and this reenforces what we already know, that space is
not entirely empty, there are particles moving about through all of
space. In the region of stars, this DM moves towards them, whilst in a
region devoid of stars, it could assume any direction.
The speed of light then is with respect to this "aether", and it has an
index of refraction just the same as any other medium, but this medium
is rather sparse and very fluid, and if taken over a large enough
distance, the currents will cancel themselves out, leaving the speed of
light as c/n relative to the "aether". c/n is of course 300,000,000m/s
or what is commonly known as c.
On the Nature of Light. Light has mass.
In a thought experiment, Einstein "proves" that light has mass. This seems to be borne out by the observation of the bending of starlight near the limb of the sun, as seen during a solar eclipse.
The thought experiment is described as this :
Exp 1. A light source (S) with a narrow beam, such as a laser, in a
lift (elevator) at 1 meter high from the lift floor is flashed on when
the lift is stationary. The beam hits the opposite side of the lift at
1 meter height where there is a vertical row of light detectors and
indicators (DI). The beam hits the detector which is at 1 meter height
as shown by its light switching on. Next, the lift is rising at a great
velocity, and the light source is flashed on again. This time the DI at
one meter does not light, but one that is lower does, and the faster
the lift is rising, the lower the DI which is activated.
This experiment “proves” that light has mass.
I shall now do another thought experiment to prove that sound has mass
:
Exp 2. Replace the light source with a sounder which can channel its
output within a narrow beam, and the target DIs are replaced with mono
directional microphones and indicators. When the lift is stationary,
the sound pulse hits the 1 meter height DI. When the lift is moving
however, the sound pulse does not hit the 1 meter high DI, but one
lower down the side of the lift. The faster the lift is moving, the
lower the DI, as proved by the appropriate light switching on.
This experiment "proves" that sound has mass.
We have here two experiments, but I have been very lax in setting out
the conditions of each. What were the conditions which Einstein (failed
to) set out in his experiment? The experiment with sound cannot be done
in a vacuum, it has to be done in air, but it can be done at varying
atmospheric pressures, and then we would discover that the mass of
sound varied in proportion to the pressure. The higher the pressure,
the less the downward movement of the sound pulse along the row of
microphones for a given lift velocity, therefore sound has less mass at
higher atmospheric pressures. It is
actually of course, caused by sound travelling faster in a higher
pressure. One further point. Is the lift an enclosed box, or is it a
lattice work frame? If an enclosed box, the air inside the lift is
entrained, and would travel with the
lift, and the sound pulse would arrive at DI no matter what the speed
of
the lift. If a lattice work frame (is this implicitly assumed in
experiment 1?), the air in the lift is stationary with respect to the
ground, and the conditions of exp. 2 would prevail. In experiment 1, is
the air entrained with and therefore having the same velocity as the
lift, or
stationary with respect to the ground? The exact argument used for
experiment 2 holds good here also. Is there in fact any air present, or
is the experiment done in a vacuum? The conditions of the original
experiment are very ambiguous.
Now some may object to my saying "...is experiment 1 done in air or a
vacuum...",
noting my disregard for the index of refraction, because a vacuum
cannot be entrained. My answer to this is that a vacuum simply does not
exist. Space is full of matter, even intergalactic space. And because
of that fact, I wish to ask a simple question, but one which will bring
howls of derision from some quarters. Can light travel through a
vacuum? That question was asked long ago, and because space was thought
to be a vacuum, the answer had to be yes. It demonstrably did so. Light
therefore had to be a particle phenomenon, and so came the discussions
about wave versus particle, and wave/particle duality, and the photon
was born.
Light is a pure wave phenomenon, it has no existence of its own; it is
just
like sound, a vibration of the atoms/molecules in the medium it is
travelling through. As the medium in intergalactic space is very
sparse, one atom per meter on average, this vibration can bridge that
gap. The mechanism by which that occurs? I am open to suggestions 
this is speculation. The fact that I do not know the answer to this key
question by no means invalidates my argument, scientists do not know
what gravity is, yet we are comfortable with equations which predict
its effect.
The fact that light is a wave answers Olber's paradox, and explains why
there
are dark patches in the sky  the Coal Sack being
perhaps the most famous (if these patches were simply matter  ie dust,
and blocking out the light from the stars behind, they would have by
now warmed up and be
reradiating). There are regions of space which are so rareified that
light cannot cross them, and a dark area is created. The density in
these areas must be less than 1 atom per meter. If there are many of
these dark areas,
they would cut off sufficient light to solve Olber's paradox. Olber's
paradox
is not solved as some claim, by light from distant parts of the
universe not having had time to reach us. This implies the truth of the
Big Bang theory,
and not only that, but that there was only one big bang.
At one time, we thought that the Earth was the centre of the
Universe. Then ditto the sun. Then we thought the sun was at the centre
of the (only) galaxy. We now know that our sun is an insignificant star
in an insignificant galaxy amongst billions (or an infinite number) of
others.
The Universe is infinite in size, and infinitely old, and within the
Universe there are big bangs occurring randomly in time and space. Step
far enough back to take a fresh look, and each one of these big bangs
looks like a galaxy, but each one is what we would call a universe 
what I call a quasiuniverse. It makes no difference whether there is
enough matter (including dark matter) in each of these quasiuniverses
to slow it's expansion and collapse it. On average, 50% will collapse
and 50% will expand forever, keeping the status quo. In this model of
the Universe, with quasiuniverses rotating about a
common centre, light from approximately half of these quasiuniverses
will have had time to reach us (assuming that at any one instant, 50%
of those which will collapse have collapsed, and are therefore going to
be reborn, and 50% of those which will not collapse have expanded to
be too cold and dim to be seen). As the Universe is infinite, that is
still an infinite number of quasiuniverses. Light therefore has had an
infinite amount of time to reach us, but has not done so because the
density of matter
in inter quasiuniversal space is too low for light to cross. Olber's
paradox
is therefore solved.
This is an update of the travelling versus the stay at home twin.
In the first preliminary step we take Earth and relocate it far into
intergalactic space. It will be far enough out such that gravity from
the nearest galaxy is a trillion times less than Earth's surface
gravity. The reason for doing this is firstly so that we don't need
to consider the gravity of surrounding stellar bodies, and secondly to
remove the motion of the Earth around the Sun and Milky Way from
consideration. Next we prevent the Earth from rotating. We do
this to avoid having to consider the SR/GR effects of the rotation
speed and the small amount of centrifugal force it provides.
Now to begin the story.
A rocket sits on the Earth's surface with a large supply of fuel.
Inside it is a room with living facilities and enough food and oxygen
to support an occupant for many months. It also contains an
accurate atomic clock. Beside the launch pad is an identically fitted
room. It contains a similar clock that has been synchronised with the
one aboard the rocket. There is also a third clock on the opposite side
of the Earth that is synchronised with the other two.
Two identical twins agree to take part in the experiment. Each will
spend the next several months either in the rocket or the Earth room,
but neither will know which. Prior to launch, they are both given a
sedative to put them to sleep. Each twin is then randomly assigned to
be moved into either the rocket or the stationary room.
The rocket lifts off. At first, very slowly so as not to apply much
acceleration. Then as it moves further from Earth and gravity
decreases, the rocket adjusts its acceleration to fill in what is
missing from Earth's gravity. This acceleration will be controlled so
that the gravity felt at all times will be exactly equal to 1G. That
is, the gravity measured by an onboard accelerometer (as the sum of
real plus artificial gravity) will measure the same as on Earth. Assume
that the rocket engine is silent and acceleration is smooth.
Shortly after launch, when the acceleration is a steady 1G, the twins
wake up. Neither of them know which room they are in. The rooms are
identical in layout and both experience what appears to be gravity. If
they drop something it will accelerate toward the floor at 9.81m/s^{2},
i.e. at 1G.
Now according to the Principle of Equivalence (also called the strong
equivalence principle), as proposed by Einstein and frequently
described by using falling elevators and rising rockets, the situation
inside the two rooms is essentially identical. That is, there is no
experiment you could devise that would allow either of the twins to
determine which room they are in. We will also assume the rooms are not
very tall. This is to prevent an occupant in the Earthroom from
measuring slightly less gravity near the ceiling.
According to the combined rules of SR and GR, will one of the clocks be
ahead of the other, and if so, what is the reason for selecting that
clock instead of the other?
The fact that the clocks are moving away from each other means there
must be a velocity present, otherwise they would remain a fixed
distance apart. Therefore, according to SR, time dilation should be
occurring and the fastermoving clock should be running more slowly.
But since the relative speed between the Earth and rocket is at all
times exactly equal from both viewpoints, there appears to be no way of
determining which is faster. As for GR, since the
acceleration / gravity situation of both rooms is exactly equal at
all times (other than the brief liftoff, when it was marginally more
than 1G), according to the Equivalence Principle it would appear we are
also unable to favour one clock over the other.
So we are left with a conundrum: either we find a way of favouring one
clock over the other or we agree that no time difference accumulates
between them.
Now an objection might be that we have no way of comparing the clocks
without one of them stopping and reversing, which would destroy the
symmetry of the situation. And so the question of which of them runs
faster up until that point is somehow hypothetical or meaningless. But
this avoids the issue because the question here is about which clock according
to the theory of SR and GR, runs slower. Unlike the
Copenhagen
Interpretation of quantum mechanics, relativity does not depend on
observers to determine the reality of a situation. So the answer to
this question won't depend on the clocks ever being compared or not.
Still, this objection can be overcome and will be addressed in the
remainder of this essay
After travelling for 10 months, and using a simple classical mechanics
calculation, we could determine that the rocket is moving at 87% the
speed of light (relative to Earth, which is now relocated outside our
galaxy). At this speed we get a Lorentz factor of 2. This might mean
that either the rocket or Earth clock is running half the speed of the
other. These numbers however are not so important because we mainly
care about which clock is ahead of the other, and not by how much
(although we are also interested in that!). So let's just pick 10
months as an arbitrary duration and assume a rough Lorentz factor of 2
at that point. This factor will be sufficient to override minor
clockdrift errors, measurement errors, and brief periods where the
acceleration of the rocket is not 1G, such as the launch and rotation
(as described later). It should also cause noticeable differences in
what the twins remember about the duration of their journey, assuming
that one is running at half the speed of the other.
So after travelling for 10 months (according to the local clock) the
occupant aboard the rocket will take a sedative. The same will occur at
the Earthroom (according to their clock). Both twins will then sleep
for a while. The rocket engine will be stopped, allowing the craft
to drift freely in space with no acceleration. It will be gently
rotated 180 degrees to face the opposite direction, now pointing at
Earth. The engine will be started again, applying an acceleration
force of exactly 1G. Both twins will then wake up.
When the rockettwin awakes, he notices no difference. Just as before,
he experiences what feels like a gravitational force of 1G toward the
floor. The Earthtwin experiences the same. The rocket is facing the
opposite direction and is now decelerating, but by all accounts
everything according to the Equivalence Principle is the same. There is
still no experiment either twin could perform to determine which is
experiencing gravity.
Therefore it would seem that according to GR, both clocks should still
be running at the same rate. And since the relative velocity is still
identical that aspect never changes, the clocks' situation is
still symmetrical according to SR.
An objection here might be that there is a difference because the
clocks are experiencing gravity in opposite direction, therefore
the clock on the rocket will now be faster or slower (pick one!) than
the one on the Earth.
For those who raise this objection, refer instead to that third clock
placed on the other side of the Earth.
It is still insynch with the first Earth clock and now experiencing
gravity in exactly the same direction as the rocket.
To continue the story, the deceleration process continues for the same
time as the original acceleration process (10 months), at which point
the rocket comes to rest relative to Earth. However the engine
doesn't stop. Instead it continues to apply exactly the same
amount of force. Deceleration becomes acceleration and the occupant
notices nothing unusual.
The acceleration continues for the next 10 months (according to the
local clock) until the rocket reaches (presumably) the original
rotation point. At this point (according to their own clocks), both
twins are put to sleep, the rocket is rotated 180 degrees, and then
starts to decelerate while pointed away from Earth. Both twins awake
and notice nothing unusual in their gravity situation.
The rocket continues its deceleration in a perfect reverse of its
original departure, steadily coming to a stop relative to Earth, and
all the while carefully adjusting its acceleration to give an onboard
experience of 1G.
Just prior to landing, both twins are put to sleep and then woken up
after landing.
The rocket has now landed beside the replica Earth room. Neither twin
has yet to emerge, and neither still has any idea which one of them was
aboard the rocket.
Not that it matters. This story was never about the twins, it was about
the atomic clocks. The twins were just there to make it interesting and
to bring it into line with historical thought experiments such as
falling elevators and the Twins Paradox.
So to state the obvious question: allowing for minor
clockdrift
errors and the brief periods of launch, landing, and rotation, when the
clocks are compared sidebyside, which of them will have recorded more
time? And why not the other way around?
And while we are at it, which of the twins will be older?
This discussion of the twins' paradox can also be found on Bernard
Burchell's web site : Alternativephysics
S light sensor
M1 mirror
(front silvered)
SR slip rings
DL1 adjustable delay line
F source of flash
MT
manual trigger
T trigger
The disc has a light sensor S on its circumference, connected
electrically via slip rings SR to the amplifier and then to the
oscilloscope
input A. At 180 degrees round the disc from the sensor, there is a
trigger T (eg hall effect) which will after amplification trigger the
scope and flash the source F when activated. There is an adjustable
delay line DL in the circuit for setting up purposes (this can be
dispensed
with if the scope has a delayed time base feature). Before
assembling S and F on the disc, to find their switch
on delays (SOD), place them adjacent to each other  ie
touching,
and activate the manual trigger. Any delay in the rise time of A is due
to the SOD and the slew rate of the amp, which should be noted and
taken
into account in later measurements when the disc is spinning.
With S and F back in place, and the disc stationary, set the disc so
the line
S to F is perpendicular to the line from the mirror M to the centre of
the disc. Activate the trigger T without moving the disc, and adjust
the DL (or the delayed time base) to trigger the scope to bring the
sharp
rise on the A trace (when the sensor is activated) to the left hand
graticule line (this will be about 10 us delay, plus whatever is needed
for the lead length differences and the SODs of F and S). Move the disc
one degree so the flash has 8.728 mm farther to travel to reach the
sensor.
With the disc stationary at this new position, check the delay between
triggering the flash and its reception at the sensor. It should be
29.11 ps.
Spin the disc at 21,600 rpm. This speed was chosen so the disc would
rotate 1 degree during the 10 us light travel time.
The flash from F takes 10 us to reach initial position of sensor S via
mirror M. In that
time the disc has rotated 1 degree.
1 degree on the circumference of a disc of 1 meter diameter is 8.728
mm,
therefore the time for light to cross that extra distance to
reach S is 29.11 ps.
As the sensor on the disc moves cicumferencially, while light travels
linearly, there is a very slight discrepancy in the distance travelled,
but the error is negligible.
If the speed of light is with respect to the sensor (the observer) :
The sensor is travelling (this is assuming a straight line distance,
but in fact it is circumferencial) away from the flash at 1,131.4 M/S,
but it will take the flash 10 us to reach S whatever the speed of S
(because S was 3000 meters away from F at the time of the
flash).
If the speed of light is with respect to its source or the medium :
The sensor is travelling away from the flash at 1,131.4 M/S. The time
taken for light to cross the extra 8,728 mm is 29.11 ps, therefore
the flash takes 10.00002911us to reach S.
The 10 us has been adjusted out by the delay line (or the delayed time
base), so the scope time base can be adjusted to see the delay of
29.11 ps between the left hand graticule line and the start of the
trace.
If distance F to S is increased to 30,000 meters, the flash now takes
100 us to reach S. In that time the disc has rotated 10 degrees.
10 degrees on the circumference of a disc of 1 meter diameter is 87.28
mm
If the speed of light is with respect to the sensor (the observer) :
The sensor is travelling away from the flash at 872.8 M/S, but it will
take the flash 100 us to reach S whatever the speed of S (because it
was
30,000 meters away from F at the time of the flash).
If the speed of light is with respect to the source or the medium :
The sensor is travelling away from the flash at 872.8 M/S. The time
taken for light to cross the extra 87.28 mm is 291.1 ps, therefore the
flash takes 10.0002911 us to reach S. Adjust the time base to see the
291.1 ps delay.
In principle the distance F to S can be increased dramatically for
easier measurement of the time difference expected. The greater the
distance F to S, the disc can be proportionally smaller/slower.
However, as the time F to S is larger, the delay line, which has to
delay the signal to the scope by the same amount of time F to S,
becomes bigger.
The greater the distance F to S, the easier the discrepancy is to
measure, but the harder the apparatus is to set up, and more
importantly, to transport. If 2 mirrors were to be placed parallel to
each other and as far apart as practicable, the flash could bounce from
one to the other many times, so increasing the path length without
unduly increasing the size of the apparatus.
Problems.
1. Is there a scope fast enough to show a difference of 29 ps? Yes,
Tektronix CSA8200 .
2. Can a disc 1 meter in diameter be spun at 21,600 rpm and held steady
at
that speed? Yes, kevlar is strong and light enough to withstand the
stress.
3. The apparatus is not portable with a distance to the mirror of 1.5
Km.
Objections.
The flash will take 10.00002911 us to reach S due to the motion of the
disc. Relativists will say that this result is because the speed of
light is with respect to the air. This was not said of the MMX, which
"proved" that the speed of light was constant in a vacuum (?!).
Unfortunately, the experiment cannot be repeated in orbit, as the light
path length to the mirror, to make any difference measurable, is too
great at 1.5 Km.
Return to menu.
The Equivalence Principle does not hold for large masses, so is
therefore wrong.
Einstein’s definition of simultaneity, upon which he builds his theory
of time dilation, is wrong.
There is no contraction along the line of motion, it is simply a visual
effect.
The speed of light is not a constant, but is with respect to the medium
it is travelling through, even a very rarefied medium such as space.
Light probably cannot propagate through a pure vacuum. There are three
somewhat arbitrary speed bands for light in space. It is fastest in
intergalactic space where the medium density is about one atom per
meter on average. Next fastest is interstellar space where the medium
is about one atom per 10 centimeters on average. Slowest is
interplanetary space where (our) medium is about one atom per
centimeter on average. These speeds are all relative to that medium,
which can be seen to be the ether, and has an average velocity of zero
when taken over a large enough distance so that the currents cancel out.
A spaceship which carries it’s own means of propulsion  e.g. a rocket
motor, can travel faster than the speed of light. The light barrier, or
Luxon Wall as some writers have dubbed it, is non existent. A problem
which will make translight speeds difficult, but not impossible, is
that of the density of matter in space. At light speed, in
interplanetary space, the space ship will encounter on average one atom
every 30 picoseconds per 1 square centimeter of frontal area. Consider
the kinetic
energy and friction on the hull.
There is no "Twin Paradox" due to velocity.
As the speed of light is not a constant, there is no time dilation
between moving (non accelerating) frames of reference. Absolute time
can be used. That is one of the constants in this universe  Time.
Return to menu.
In chapter VI, Einstein has a man walking along in the carriage in the
direction of motion, and discusses the classical addition of
velocities. If w is the speed of the man with reference to the train,
and v is the speed of the train relative to the embankment, then W is
the speed of the man relative to the embankment W = v + w.
In chapter VII, he swaps the man for a light beam. Quote "It is obvious
that we can here apply the considerations of the previous section,
since the ray of light plays the part of the man walking along
relatively to the carriage."
However, quote "If a ray of light be sent along the embankment..."
notice that the 2 situations are different. The man in chapter VI is in
the carriage, while the ray of light in chapter VII is on the
embankment. "Let us enquire about the velocity of propagation of the
ray of light relative to the carriage... and we have w = c  v " If he
hadn't swapped IFRs, the velocity of propagation would have come out at
c. It was precisely because the answer was less than c, that SRT was
born, and all that it entails. This error also has a direct bearing on
the thought experiment in chapter IX. The man on the train "...is
hastening towards the beam of light..."
Another error is this :
This error is to be found in his 1905 paper, presumably it was pointed
out to him as it is not present in his later book "Relativity  The
special And The General Theory". After establishing that time runs at
different rates in different IFRs, he goes on to show how to
synchronise clocks in IFR A and IFR B.
"We have so far defined only an ``A time'' and a ``B time.'' We have
not defined a common ``time'' for A and B, for the latter cannot be
defined at all unless we establish by definition that the ``time''
required by light to travel from A to B equals the ``time'' it requires
to travel from B to A.
Let a ray of light start at the ``A time'' tA from
A towards B, let it at the ``B time'' tB be reflected at B in the
direction of A, and arrive again at A at the ``A time'' t'A.
In accordance with definition the two clocks synchronize if
tB  tA = t'A  tB
At first glance this looks reasonable, but look closer. The sum above
is meaningless unless the clocks at A and at B are synchronized
already. If B is ticking at a different rate to A (which Einstein says
it is) the result is nonsense. "This equation does not define
synchronized clocks, but requires them" . Quote from "Relativity
Unraveled"
This error was brought to my attention by Hans Zweig.
I am indebted to my friend Hans J Zweig for his support in our ongoing
battle to unseat SRT. He has published a book called "Relativity
Unraveled", which I thoroughly recommend to anybody who has any
questions at all about SRT, or who simply thinks that it is wrong. A
preview of it is here : http://www.relativityunraveled.net.
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